Integrand size = 24, antiderivative size = 101 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=\frac {\left (b^2-4 a c\right )^3}{1152 c^4 d^{10} (b+2 c x)^9}-\frac {3 \left (b^2-4 a c\right )^2}{896 c^4 d^{10} (b+2 c x)^7}+\frac {3 \left (b^2-4 a c\right )}{640 c^4 d^{10} (b+2 c x)^5}-\frac {1}{384 c^4 d^{10} (b+2 c x)^3} \]
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Time = 0.06 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {697} \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=\frac {\left (b^2-4 a c\right )^3}{1152 c^4 d^{10} (b+2 c x)^9}-\frac {3 \left (b^2-4 a c\right )^2}{896 c^4 d^{10} (b+2 c x)^7}+\frac {3 \left (b^2-4 a c\right )}{640 c^4 d^{10} (b+2 c x)^5}-\frac {1}{384 c^4 d^{10} (b+2 c x)^3} \]
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Rule 697
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (-b^2+4 a c\right )^3}{64 c^3 d^{10} (b+2 c x)^{10}}+\frac {3 \left (-b^2+4 a c\right )^2}{64 c^3 d^{10} (b+2 c x)^8}+\frac {3 \left (-b^2+4 a c\right )}{64 c^3 d^{10} (b+2 c x)^6}+\frac {1}{64 c^3 d^{10} (b+2 c x)^4}\right ) \, dx \\ & = \frac {\left (b^2-4 a c\right )^3}{1152 c^4 d^{10} (b+2 c x)^9}-\frac {3 \left (b^2-4 a c\right )^2}{896 c^4 d^{10} (b+2 c x)^7}+\frac {3 \left (b^2-4 a c\right )}{640 c^4 d^{10} (b+2 c x)^5}-\frac {1}{384 c^4 d^{10} (b+2 c x)^3} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.78 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=\frac {35 \left (b^2-4 a c\right )^3-135 \left (b^2-4 a c\right )^2 (b+2 c x)^2+189 \left (b^2-4 a c\right ) (b+2 c x)^4-105 (b+2 c x)^6}{40320 c^4 d^{10} (b+2 c x)^9} \]
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Time = 2.39 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.20
method | result | size |
default | \(\frac {-\frac {12 a c -3 b^{2}}{640 c^{4} \left (2 c x +b \right )^{5}}-\frac {1}{384 c^{4} \left (2 c x +b \right )^{3}}-\frac {48 a^{2} c^{2}-24 a \,b^{2} c +3 b^{4}}{896 c^{4} \left (2 c x +b \right )^{7}}-\frac {64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}}{1152 c^{4} \left (2 c x +b \right )^{9}}}{d^{10}}\) | \(121\) |
risch | \(\frac {-\frac {c^{2} x^{6}}{6}-\frac {b c \,x^{5}}{2}+\left (-\frac {3 a c}{10}-\frac {11 b^{2}}{20}\right ) x^{4}-\frac {b \left (9 a c +4 b^{2}\right ) x^{3}}{15 c}-\frac {\left (15 a^{2} c^{2}+24 a \,b^{2} c +4 b^{4}\right ) x^{2}}{70 c^{2}}-\frac {b \left (30 a^{2} c^{2}+6 a \,b^{2} c +b^{4}\right ) x}{140 c^{3}}-\frac {140 c^{3} a^{3}+30 a^{2} b^{2} c^{2}+6 a \,b^{4} c +b^{6}}{2520 c^{4}}}{d^{10} \left (2 c x +b \right )^{9}}\) | \(152\) |
gosper | \(-\frac {420 c^{6} x^{6}+1260 b \,c^{5} x^{5}+756 a \,c^{5} x^{4}+1386 b^{2} c^{4} x^{4}+1512 a b \,c^{4} x^{3}+672 x^{3} b^{3} c^{3}+540 a^{2} c^{4} x^{2}+864 a \,b^{2} c^{3} x^{2}+144 x^{2} b^{4} c^{2}+540 a^{2} b \,c^{3} x +108 x a \,b^{3} c^{2}+18 x \,b^{5} c +140 c^{3} a^{3}+30 a^{2} b^{2} c^{2}+6 a \,b^{4} c +b^{6}}{2520 \left (2 c x +b \right )^{9} d^{10} c^{4}}\) | \(166\) |
norman | \(\frac {\frac {a^{3} x}{b d}+\frac {\left (16 c \,a^{3}+3 a^{2} b^{2}\right ) x^{2}}{2 b^{2} d}+\frac {\left (112 a^{3} c^{2}+24 a^{2} b^{2} c +3 a \,b^{4}\right ) x^{3}}{3 b^{3} d}+\frac {\left (448 c^{3} a^{3}+96 a^{2} b^{2} c^{2}+18 a \,b^{4} c +b^{6}\right ) x^{4}}{4 b^{4} d}+\frac {32 c^{4} \left (140 c^{3} a^{3}+30 a^{2} b^{2} c^{2}+6 a \,b^{4} c +b^{6}\right ) x^{8}}{35 b^{8} d}+\frac {64 c^{3} \left (140 c^{3} a^{3}+30 a^{2} b^{2} c^{2}+6 a \,b^{4} c +b^{6}\right ) x^{7}}{35 b^{7} d}+\frac {c \left (2240 c^{3} a^{3}+480 a^{2} b^{2} c^{2}+96 a \,b^{4} c +11 b^{6}\right ) x^{5}}{10 b^{5} d}+\frac {c^{2} \left (8960 c^{3} a^{3}+1920 a^{2} b^{2} c^{2}+384 a \,b^{4} c +59 b^{6}\right ) x^{6}}{30 b^{6} d}+\frac {64 c^{5} \left (140 c^{3} a^{3}+30 a^{2} b^{2} c^{2}+6 a \,b^{4} c +b^{6}\right ) x^{9}}{315 b^{9} d}}{d^{9} \left (2 c x +b \right )^{9}}\) | \(349\) |
parallelrisch | \(\frac {35840 x^{9} a^{3} c^{8}+7680 x^{9} a^{2} b^{2} c^{7}+1536 x^{9} a \,b^{4} c^{6}+256 x^{9} b^{6} c^{5}+161280 x^{8} a^{3} b \,c^{7}+34560 x^{8} a^{2} b^{3} c^{6}+6912 x^{8} a \,b^{5} c^{5}+1152 x^{8} b^{7} c^{4}+322560 x^{7} a^{3} b^{2} c^{6}+69120 x^{7} a^{2} b^{4} c^{5}+13824 x^{7} a \,b^{6} c^{4}+2304 x^{7} b^{8} c^{3}+376320 x^{6} a^{3} b^{3} c^{5}+80640 x^{6} a^{2} b^{5} c^{4}+16128 x^{6} a \,b^{7} c^{3}+2478 x^{6} b^{9} c^{2}+282240 x^{5} a^{3} b^{4} c^{4}+60480 x^{5} a^{2} b^{6} c^{3}+12096 x^{5} a \,b^{8} c^{2}+1386 x^{5} b^{10} c +141120 x^{4} a^{3} b^{5} c^{3}+30240 x^{4} a^{2} b^{7} c^{2}+5670 x^{4} a \,b^{9} c +315 x^{4} b^{11}+47040 x^{3} a^{3} b^{6} c^{2}+10080 x^{3} a^{2} b^{8} c +1260 x^{3} a \,b^{10}+10080 x^{2} a^{3} b^{7} c +1890 x^{2} a^{2} b^{9}+1260 a^{3} b^{8} x}{1260 b^{9} d^{10} \left (2 c x +b \right )^{9}}\) | \(379\) |
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Leaf count of result is larger than twice the leaf count of optimal. 280 vs. \(2 (93) = 186\).
Time = 0.39 (sec) , antiderivative size = 280, normalized size of antiderivative = 2.77 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=-\frac {420 \, c^{6} x^{6} + 1260 \, b c^{5} x^{5} + b^{6} + 6 \, a b^{4} c + 30 \, a^{2} b^{2} c^{2} + 140 \, a^{3} c^{3} + 126 \, {\left (11 \, b^{2} c^{4} + 6 \, a c^{5}\right )} x^{4} + 168 \, {\left (4 \, b^{3} c^{3} + 9 \, a b c^{4}\right )} x^{3} + 36 \, {\left (4 \, b^{4} c^{2} + 24 \, a b^{2} c^{3} + 15 \, a^{2} c^{4}\right )} x^{2} + 18 \, {\left (b^{5} c + 6 \, a b^{3} c^{2} + 30 \, a^{2} b c^{3}\right )} x}{2520 \, {\left (512 \, c^{13} d^{10} x^{9} + 2304 \, b c^{12} d^{10} x^{8} + 4608 \, b^{2} c^{11} d^{10} x^{7} + 5376 \, b^{3} c^{10} d^{10} x^{6} + 4032 \, b^{4} c^{9} d^{10} x^{5} + 2016 \, b^{5} c^{8} d^{10} x^{4} + 672 \, b^{6} c^{7} d^{10} x^{3} + 144 \, b^{7} c^{6} d^{10} x^{2} + 18 \, b^{8} c^{5} d^{10} x + b^{9} c^{4} d^{10}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 298 vs. \(2 (102) = 204\).
Time = 5.01 (sec) , antiderivative size = 298, normalized size of antiderivative = 2.95 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=\frac {- 140 a^{3} c^{3} - 30 a^{2} b^{2} c^{2} - 6 a b^{4} c - b^{6} - 1260 b c^{5} x^{5} - 420 c^{6} x^{6} + x^{4} \left (- 756 a c^{5} - 1386 b^{2} c^{4}\right ) + x^{3} \left (- 1512 a b c^{4} - 672 b^{3} c^{3}\right ) + x^{2} \left (- 540 a^{2} c^{4} - 864 a b^{2} c^{3} - 144 b^{4} c^{2}\right ) + x \left (- 540 a^{2} b c^{3} - 108 a b^{3} c^{2} - 18 b^{5} c\right )}{2520 b^{9} c^{4} d^{10} + 45360 b^{8} c^{5} d^{10} x + 362880 b^{7} c^{6} d^{10} x^{2} + 1693440 b^{6} c^{7} d^{10} x^{3} + 5080320 b^{5} c^{8} d^{10} x^{4} + 10160640 b^{4} c^{9} d^{10} x^{5} + 13547520 b^{3} c^{10} d^{10} x^{6} + 11612160 b^{2} c^{11} d^{10} x^{7} + 5806080 b c^{12} d^{10} x^{8} + 1290240 c^{13} d^{10} x^{9}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 280 vs. \(2 (93) = 186\).
Time = 0.21 (sec) , antiderivative size = 280, normalized size of antiderivative = 2.77 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=-\frac {420 \, c^{6} x^{6} + 1260 \, b c^{5} x^{5} + b^{6} + 6 \, a b^{4} c + 30 \, a^{2} b^{2} c^{2} + 140 \, a^{3} c^{3} + 126 \, {\left (11 \, b^{2} c^{4} + 6 \, a c^{5}\right )} x^{4} + 168 \, {\left (4 \, b^{3} c^{3} + 9 \, a b c^{4}\right )} x^{3} + 36 \, {\left (4 \, b^{4} c^{2} + 24 \, a b^{2} c^{3} + 15 \, a^{2} c^{4}\right )} x^{2} + 18 \, {\left (b^{5} c + 6 \, a b^{3} c^{2} + 30 \, a^{2} b c^{3}\right )} x}{2520 \, {\left (512 \, c^{13} d^{10} x^{9} + 2304 \, b c^{12} d^{10} x^{8} + 4608 \, b^{2} c^{11} d^{10} x^{7} + 5376 \, b^{3} c^{10} d^{10} x^{6} + 4032 \, b^{4} c^{9} d^{10} x^{5} + 2016 \, b^{5} c^{8} d^{10} x^{4} + 672 \, b^{6} c^{7} d^{10} x^{3} + 144 \, b^{7} c^{6} d^{10} x^{2} + 18 \, b^{8} c^{5} d^{10} x + b^{9} c^{4} d^{10}\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.63 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=-\frac {420 \, c^{6} x^{6} + 1260 \, b c^{5} x^{5} + 1386 \, b^{2} c^{4} x^{4} + 756 \, a c^{5} x^{4} + 672 \, b^{3} c^{3} x^{3} + 1512 \, a b c^{4} x^{3} + 144 \, b^{4} c^{2} x^{2} + 864 \, a b^{2} c^{3} x^{2} + 540 \, a^{2} c^{4} x^{2} + 18 \, b^{5} c x + 108 \, a b^{3} c^{2} x + 540 \, a^{2} b c^{3} x + b^{6} + 6 \, a b^{4} c + 30 \, a^{2} b^{2} c^{2} + 140 \, a^{3} c^{3}}{2520 \, {\left (2 \, c x + b\right )}^{9} c^{4} d^{10}} \]
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Time = 9.77 (sec) , antiderivative size = 268, normalized size of antiderivative = 2.65 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^{10}} \, dx=-\frac {\frac {140\,a^3\,c^3+30\,a^2\,b^2\,c^2+6\,a\,b^4\,c+b^6}{2520\,c^4}+x^4\,\left (\frac {11\,b^2}{20}+\frac {3\,a\,c}{10}\right )+\frac {c^2\,x^6}{6}+\frac {x^2\,\left (15\,a^2\,c^2+24\,a\,b^2\,c+4\,b^4\right )}{70\,c^2}+\frac {b\,c\,x^5}{2}+\frac {x^3\,\left (4\,b^3+9\,a\,c\,b\right )}{15\,c}+\frac {b\,x\,\left (30\,a^2\,c^2+6\,a\,b^2\,c+b^4\right )}{140\,c^3}}{b^9\,d^{10}+18\,b^8\,c\,d^{10}\,x+144\,b^7\,c^2\,d^{10}\,x^2+672\,b^6\,c^3\,d^{10}\,x^3+2016\,b^5\,c^4\,d^{10}\,x^4+4032\,b^4\,c^5\,d^{10}\,x^5+5376\,b^3\,c^6\,d^{10}\,x^6+4608\,b^2\,c^7\,d^{10}\,x^7+2304\,b\,c^8\,d^{10}\,x^8+512\,c^9\,d^{10}\,x^9} \]
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